Introduction to Ideal Gas Law Relationships

NAME:  Hope Fluegel

TITLE OF LESSON: Introduction to Ideal Gas Law Relationships

LENGTH OF LESSON:  50 minutes

NAME OF COURSE:  Chemistry 

GRADE LEVEL:  High School

 

SOURCE OF THIS LESSON:

Pressure Chamber. < http://jersey.uoregon.edu/vlab/Piston/

McBane, George. Gas Laws. <http://www.chemistry.ohio-state.edu/betha/nealGasLaw/index.html>

 

TEKS ADDRESSED:

 

¤112.45. Chemistry.

(7)  Science concepts. The student knows the variables that influence the behavior of gases. The student is expected to:

(A)  describe interrelationships among temperature, particle number, pressure, and volume of gases contained within a closed system; and

 

 

PERFORMANCE OR LEARNER OUTCOMES:

Students will be able to:

¤         Understand relationship between variables (Pressure and Volume at Constant Temp)

¤         State the assumptions made by the ideal gas law and explain why they are being made

¤         Find the answer to an ideal gas problem

 

RESOURCES, MATERIAL AND SUPPLIES NEEDED:

¤         Computers with internet connections

 

SUPPLEMENTARY MATERIALS, HANDOUTS: 

¤         None (have students answer experimental questions in their lab notebook)

 

 

 

LESSON PLAN

Engagement:

 

Give brief review of gasses using the following website:

 

http://www.chemistry.ohio-state.edu/betha/nealGasLaw/index.html

 

 

Exploration:

 

Have students explore http://jersey.uoregon.edu/vlab/Piston/

and complete each experiment.

 

 

 

Explanation: Discuss answers to each experiment.

 

 

 

Elaboration:

 

The ideal gas law is not perfect. It makes a lot of assumptions that are not actually true. It assumes:

¤         Molecules take up no space

 

 

 

¤         No forces (attractive/repulsive) between molecules

 

 

¤         Elastic collisions with walls

 

 

 

 

 

Is this true? Is this a good approximation? Why or why not?

 

Is this true? Is this a good approximation? Why or why not?

 

Is this true? Is this a good approximation? Why or why not?

 

Evaluation:

 

 

 

An automobile is driven by chemical reactions which can be reasonably modeled by the combustion of octane. It takes about one mole of octane to move a car one mile.

What volume of oxygen at 300K and 1.00 atm is required to react with one mole of octane according to the reaction given below?

2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O

What volume of air is required, given that air is 21% oxygen?

Solution step 1: From the reaction stoichiometry, 25/2 moles of oxygen are required to burn one mole of octane.

Solution step 2: Determine the volume of 25/2 moles of oxygen at 300K and 1.00 atm.
V = nRT/P = ( (12.5 mol)(0.0821L atm mol-1 K-1)(300. K) ) /(1.00 atm) = 308 L

Solution step 3: Determine the volume of air required.
Vair = (308L O2) x (100L air)/(21L O2) = 1470 L air